Chapter 5 Polynomials and Polynomial Functions - 5.1 Use Properties of Exponents - 5.1 Exercises - Skill Practice - Page 334: 46

$(x^{12} y^{16})=(x^{6} y^{8}) \times (x^{6} y^{8}) $

Here, we have $(x^{12} y^{16})=(x^1 y^{1}) (x^{11}y^{15})$ This gives: $(x^{12} y^{16})=x^{2} y^{6} \times x^{10} y^{10}$ or, $(x^{12} y^{16})=(x^{2} y^{6}) \times (x^{10} y^{10})$ Hence, $(x^{12} y^{16})=(x^{6} y^{8}) \times (x^{6} y^{8}) $