Answer
See the graph
Work Step by Step
$y=x^2+4$
The function is already in quadratic standard form $y=ax^2+bx+c$
with $a=1, b=0, c=4$.
Find the x-coordinate: $x=-\frac{b}{2a}=-\frac{0}{2.1}=0$
Substitute for x: $y=0^2+4 \rightarrow y=4$
The vertex is $(0,4)$
Also the axis of symmetry is $x=0$
Find some other points:
$x=-1 \rightarrow y=5$
$x=1 \rightarrow y=5$
$x=-2 \rightarrow y=8$
$x=2 \rightarrow y=8$