Answer
$$x=-5/6\pm (1/6)\sqrt{23}i$$
Work Step by Step
We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain:
$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
$$x=\frac{-5\pm \sqrt{(5)^2-4(3)(4)}}{2(3)}$$
$$x=-5/6\pm (1/6)\sqrt{23}i$$
