Chapter 4 Quadratic Functions and Factoring - 4.10 Write Quadratic Functions and Models - 4.10 Exercises - Quiz for Lessons 4.8-4.10 - Page 315: 2

$$x=2\pm .5\sqrt{14}$$

We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain: $$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$ $$x=\frac{8\pm \sqrt{(-8)^2-4(2)(1)}}{2(2)}$$ $$x=2\pm .5\sqrt{14}$$