Answer
$y=(x-5)^{2}+7$
Work Step by Step
We already know $y$, $x$, $k$ and $h$ from the given vertex and point, so in order to get the quadratic function we need to find $a$...
$y=a(x-h)^{2}+k$
$11=a(3-5)^{2}+7$
$4=a(-2)^{2}$
$4=4a$
$a=\frac{4}{4}$
$a=1$
Therefore the function is...
$y=(x-5)^{2}+7$