Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - Chapter Test - Page 227: 22

Answer

$A(C-B)=\begin{bmatrix} -31 & -27\\ -69 & -33 \end{bmatrix}$

Work Step by Step

$A(C-B)=\begin{bmatrix} 1 & -2 \\ 4 & -3 \end{bmatrix}(\begin{bmatrix} -6 & 8 \\ 10 & 15 \end{bmatrix}-\begin{bmatrix} 3 & 5\\ -1 & 0 \end{bmatrix})$ $=\begin{bmatrix} 1 & -2 \\ 4&-3 \end{bmatrix}\begin{bmatrix} -9 & 3 \\ 11 & 15 \end{bmatrix}$ $=\begin{bmatrix} -31 & -27\\ -69 & -33 \end{bmatrix}$
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