Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - Chapter Test - Page 227: 14

Answer

The solution is $(-\frac{4}{3},-\frac{17}{3},\frac{26}{3})$

Work Step by Step

Rewrite the system as a linear system in two variables. Add Equation 1 and Equation 3. $ 2x - 5y- z = 17$ $-4x + 6y + z=-20$ __________________________ $-2x+y=-3$ $ 6x - 15y - 3z = 51$ $x + y + 3z = 19$ __________________________ $7x-14y=70$ Solve the new linear system for both of its variables. $-2x+y=-3$ $7x-14y=70$ Add $14$ times new Equation 1 to new Equation 2: $-28x+14y=-42$ $7x-14y=70$ ___________________ $-21x=28$ $x=-\frac{4}{3}$ Solve for y: $7(-\frac{4}{3})-14y=70$ $y=-\frac{17}{3}$ Solve for z: $-\frac{4}{3}-\frac{17}{3}+3z=19$ $z=\frac{26}{3}$ The solution is $(-\frac{4}{3},-\frac{17}{3},\frac{26}{3})$.
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