Answer
See below
Work Step by Step
We have $l_1=16\\l_n=16(0.9)^{n-1}$
Since the ratio is less than 1, the length will be finite.
Obtain: $\sum^{\infty}_{i=0}16(0.9)^i=\frac{a}{1-r}=\frac{16}{1-0.9}=160$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - Mixed Review of Problem Solving - Lessons 12.4-12.5 - Page 838: 6
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