Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - Mixed Review of Problem Solving - Lessons 12.4-12.5 - Page 838: 3

Answer

See below

Work Step by Step

The first three iterations are: $$x_1=f(x_0)=x^2_0-8=2^2-8=-4\\x_2=f(x_1)=x_1^2-8=(-4)^2-8=8\\x_3=f(x_2)=x_2^2-8=8^2-8=56$$ The sum is $-4+8+56=60$
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