Answer
$104$
Work Step by Step
We know that $\sum_{i=1}^n(i)=\frac{n(n+1)}{2}$
Hence $\sum_{i=1}^{16}(-2+i)=16(-2)+\sum_{i=1}^{16}(i)=-32+\frac{16(16+1)}{2}=104$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - Cumulative Review - Page 848: 38
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