Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - Cumulative Review - Page 848: 33

Answer

See below.

Work Step by Step

The mean of $n$ numbers is the sum of the numbers divided by $n$. The median of $n$ is the middle number of the numbers when they are in order (and the mean of the middle $2$ numbers if $n$ is even). The mode of $n$ numbers is the number or numbers that appear(s) most frequently. Hence here the mean: $\frac{216+ 203+ 225+ 216+ 212+ 228+ 209 }{7}=215.571$ The median is the middle item in the sequence $ 203,209,212,216,216, 225, 228$, which is: $216$. The mode is $216$. The range is the difference between the largest and the smallest data value. The standard deviation of $x_1,x_2,...,x_n$ is (where $\overline{x}$ is the mean of the data values): $\sqrt{\frac{(x_1-\overline{x})^2+(x_2-\overline{x})^2+...+(x_n-\overline{x})^2}{n}}$. Hence here the range is: $228-203=25$ and the standard deviation is: $\sqrt{\frac{(216-215.571)^2+(203-215.571)^2+...+(209-215.571)^2}{7}}\approx8.086$
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