Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - Cumulative Review - Page 848: 27

Answer

1

Work Step by Step

We know the equation for combinations: $$_nC_r = \frac{n!}{r!\left(n-r\right)!}$$ Thus, we find: $$\frac{6!}{6!\left(6-6\right)!}=1$$
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