Answer
$70$
Work Step by Step
Here, we have the first term: $i_1=(1)^2+3=4$;
Second Term: $i_2=(2)^2+3=7$;
Third Term: $i_3=(3)^2+3=12$;
Fourth Term: $i_4=(4)^2+3=19$
Last Term: $i_5=(5)^2+3=28$;
Add all the terms: $S_i=4+7+12+19+28=70$