Chapter 12 Sequences and Series - 12.1 Define and Use Sequences and Series - 12.1 Exercises - Skill Practice - Page 798: 22

n-th term:$\quad a_{n}=\displaystyle \frac{2n-1}{10n}$ The next term is $\displaystyle \quad a_{5}=\frac{9}{50}$

The n-th numerator is the n-th odd number $\quad (2n-1)$ The nth denominator is the n-th multiple of 10, $\quad (10n)$ So, the nth term is $a_{n}=\displaystyle \frac{2n-1}{10n}$, and the next term is $a_{5}=\displaystyle \frac{2(5)-1}{10(5)}=\frac{9}{50}$