Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - 12.1 Define and Use Sequences and Series - 12.1 Exercises - Skill Practice - Page 798: 19

Answer

n-th term:$\quad a_{n}=\displaystyle \frac{2}{3n}$ The next term is $\displaystyle \quad a_{5}=\frac{2}{15}$

Work Step by Step

The n-th numerator is always 2. The nth denominator is a multiple of 3, starting with $3(1).$ So, the nth term is $a_{n}=\displaystyle \frac{2}{3n}$, and the next term is $a_{5}=\displaystyle \frac{2}{3\cdot 5}=\frac{2}{15}$
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