Answer
$0.8413$
Work Step by Step
$\overline{x}=np=0.25\cdot192=48$
$\sigma=\sqrt{np(1-p)}=\sqrt{192(0.75)(0.25)}=6$
Thus $P(x\geq42)=1-P(x\leq42)\approx 1-P(z\leq\frac{42-48}{6})=1-P(z\leq-1)=1-0.1587=0.8413$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 11 Data Analysis and Statistics - Extension - Approximate Binomial Distributions and Test Hypotheses - Practice - Page 765: 16
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