Answer
$0.2119$
Work Step by Step
$\overline{x}=np=0.04\cdot460=18.4$
$\sigma=\sqrt{np(1-p)}=\sqrt{460(0.04)(0.96)}\approx4.2$
Thus $P(x\leq15)\approx P(z\leq\frac{15-18.4}{4.2})\approx P(z\leq-0.8)=0.2119$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 11 Data Analysis and Statistics - Extension - Approximate Binomial Distributions and Test Hypotheses - Practice - Page 765: 10
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
