Answer
$0.9332$
Work Step by Step
$\overline{x}=np=0.04\cdot460=18.4$
$\sigma=\sqrt{np(1-p)}=\sqrt{460(0.04)(0.96)}\approx4.2$
Thus $P(x\geq12)=1-P(x\leq12)\approx 1-P(z\leq\frac{12-18.4}{4.2})\approx 1-P(z\leq-1.5)=1-0.0668=0.9332$
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