Answer
$0.9782$
Work Step by Step
$\text{z-score}=\frac{\text{data item-mean}}{\text{standard deviation}}$
Hence here the z-score is: $\frac{62-72}{5}=-2$
Then, using the table: $P(62\leq x)=1-P(x\leq 62)\approx1-P(z\leq-2)=1-0.0228=0.9782$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 11 Data Analysis and Statistics - Chapter Test - Page 787: 6
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