Answer
$0.4987$
Work Step by Step
$\text{z-score}=\frac{\text{data item-mean}}{\text{standard deviation}}$
Hence here the z-score is: $\frac{57-72}{5}=-1,\frac{72-72}{5}=0$
Then, using the table: $P(57\leq x\leq 72)=P(x\leq 72)-P(x\leq57)\approx P(z\leq0)-P(z\leq-3)=0.5-0.0013=0.4987$
