Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - Chapter Test - Page 787: 4

Answer

$0.6826$

Work Step by Step

$\text{z-score}=\frac{\text{data item-mean}}{\text{standard deviation}}$ Hence here the z-score is: $\frac{67-72}{5}=-1,\frac{77-72}{5}=1$ Then, using the table: $P(67\leq x\leq 77)=P(x\leq 77)-P(x\leq67)\approx P(z\leq1)-P(z\leq-1)=0.8413-0.1587=0.6826$
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