Answer
$0.0179$
Work Step by Step
$\text{z-score}=\frac{\text{data item-mean}}{\text{standard deviation}}$
Hence here the z-score is: $\frac{50-95}{7}\approx-6.4,\frac{80-95}{7}\approx-2.1$
Then, using the table: $P(50\lt x\leq80)=P(x\leq80)-P(x\leq50)\approx P(z\leq-2.1)-P(z\leq-6.4)=0.0179-0.000=0.0179$
