Answer
$0.242$
Work Step by Step
$\text{z-score}=\frac{\text{data item-mean}}{\text{standard deviation}}$
Hence here the z-score is: $\frac{100-95}{7}\approx0.7$
Then, using the table: $P(x\gt100)=1-P(x\leq100)\approx 1-P(z\leq0.7)=1-0.7580=0.242$
