Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - Chapter Review - Page 785: 11

Answer

See below.

Work Step by Step

The mean of $n$ numbers is the sum of the numbers divided by $n$. The median of $n$ is the middle number of the numbers when they are in order (and the mean of the middle $2$ numbers if $n$ is even). The mode of $n$ numbers is the number or numbers that appear(s) most frequently. Hence here the mean is $\frac{14.9+ 14.3+ 20.1+ 30.5+ 76.9+ 59.8+ 57.2+ 40.2+ 59.8+ 46.5+ 16.4+ 18.8}{12}=37.95$; the median is the mean of the middle items in the sequence $14.3, 14.9, 16.4, 18.8, 20.1, 30.5,40.2,46.5,57.2,59.8,59.8, 76.9$ which is: $(30.5+40.2)/2=35.35$; and the mode is $59.8$. The range is the difference between the largest and the smallest data value. The standard deviation of $x_1,x_2,...,x_n$ is (where $\overline{x}$ is the mean of the data values): $\sqrt{\frac{(x_1-\overline{x})^2+(x_2-\overline{x})^2+...+(x_n-\overline{x})^2}{n}}$. Hence here the range is: $76.9-14.3=62.6$ and the standard deviation is: $\sqrt{\frac{(14.9-37.95)^2+(14.3-37.95)^2+...+(76.9-37.95)^2}{12-1}}\approx21.7769$ When every value of a data set is multiplied by a constant, the new mean, median, mode, range, and standard deviation can be obtained by multiplying each original value by the constant. Here the constant is $0.03937$, hence in inches the mean is: $37.95\cdot 0.03937=1.494$ The median is: $35.35\cdot 0.03937=1.392$. The mode is: $59.8\cdot 0.03937=2.354$ The range is: $62.6\cdot 0.03937=2.465$ The standard deviation is: $21.7769\cdot 0.03937=0.857$.
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