Chapter 11 Data Analysis and Statistics - 11.3 Use Normal Distributions - 11.3 Exercises - Skill Practice - Page 760: 26

$0.6709$

$\text{z-score}=\frac{\text{data item-mean}}{\text{standard deviation}}$ Hence here the z-score is: $\frac{75-64}{7}\approx 1.6,\frac{60-64}{7}\approx -0.6$ Then, using the table: $P(60\lt x\leq 75)=P(x\leq 75)-P(x\leq60)\approx P(z\leq1.6)-P(z\leq-0.6)=0.9452-0.2743=0.6709$