Chapter 11 Data Analysis and Statistics - 11.3 Use Normal Distributions - 11.3 Exercises - Skill Practice - Page 760: 25

$0.0548$

$\text{z-score}=\frac{\text{data item-mean}}{\text{standard deviation}}$ Hence here the z-score is: $\frac{75-64}{7}\approx 1.6$ Then, using the table: $P(x\gt 75)=1-P(x\leq 75)\approx1-P(z\leq1.6)=1-0.9452=0.0548$