Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - 11.3 Use Normal Distributions - 11.3 Exercises - Skill Practice - Page 760: 22

Answer

$0.0808$

Work Step by Step

$\text{z-score}=\frac{\text{data item-mean}}{\text{standard deviation}}$ Hence here the z-score is: $\frac{54-64}{7}\approx -1.4$ Then, using the table: $P(x\leq 54)\approx P(z\leq -1.4)=0.0808$
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