Answer
See below
Work Step by Step
The mean, median, mode, range, and standard deviation of the data set when the outlier is included:
$\bar x=\frac{60+66+66+68+71+72+75+78+80+152}{10}=78.8\\ Median =71.5\\Mode =66\\Range=92\\\sigma =\sqrt \frac{(60-78.8)^2+(66-78.8)^2+(66-78.8)^2+(68-78.8)^2+(71-78.8)^2+(72-78.8)^2+(75-78.8)^2+(78-78.8)^2+(80-78.8)^2+(152-78.8)^2}{10}=25.06$
The mean, median, mode, range, and standard deviation of the data set when the outlier is not included:
$\bar x=\frac{60+66+66+68+71+72+75+78+80}{9}=70.67\\ Median =71\\Mode =66\\Range=20\\\sigma =\sqrt \frac{(60-70.67)^2+(66-70.67)^2+(66-70.67)^2+(68-70.67)^2+(71-70.67)^2+(72-70.67)^2+(75-70.67)^2+(78-70.67)^2+(80-70.67)^2}{9}=6.02$