Answer
See below.
Work Step by Step
The mean of $n$ numbers is the sum of the numbers divided by $n$.
The range is the difference between the largest and the smallest data value. The standard deviation of $x_1,x_2,...,x_n$ is (where $\overline{x}$ is the mean of the data values): $\sqrt{\frac{(x_1-\overline{x})^2+(x_2-\overline{x})^2+...+(x_n-\overline{x})^2}{n}}$.
Hence here the mean is: $\frac{3.1+2.7+6.0+5.6+2.3+2.0+1.3 }{7}=3.286$
Hence here the range is: $6-1.3=4.7$, and the standard deviation is: $\sqrt{\frac{(10-3.286)^2+(12-3.286)^2+...+(9-3.286)^2}{7}}\approx1.81$
