Answer
See below
Work Step by Step
The mean, median, mode, range, and standard deviation of the data set when the outlier is included:
$\bar x=\frac{2+2+3+3+4+4+4+68+6}{9}=10.67\\ Median = 4\\Mode =4\\Range=68-2=66\\\sigma =\sqrt \frac{(2-10.67)^2+(2-10.67)^2+(3-10.67)^2+(3-10.67)^2+(4-10.67)^2+(4-10.67)^2+(4-10.67)^2(6-10.67)^2+(68-10.67)^2}{9}=20.3$
The mean, median, mode, range, and standard deviation of the data set when the outlier is excluded:
$\bar x=\frac{2+2+3+3+4+4+4+6}{8}=3.5\\ Median = 3.5\\Mode =4\\Range=6-2=4\\\sigma =\sqrt \frac{(2-3.5)^2+(2-3.5)^2+(3-3.5)^2+(3-3.5)^2+(4-3.5)^2+(4-3.5)^2+(4-3.5)^2+(6-3.5)^2}{8}=1.22$