Answer
$$x^{12}-4x^9y^2+6x^6y^4-4x^3y^6+y^8$$
Work Step by Step
We know from the Binomial Theorem (page 693) that we can expand the given expression without multiplying it out. Doing this, we obtain:
$$x^{12}-4x^9y^2+6x^6y^4-4x^3y^6+y^8$$
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