Chapter 9 - Quadratic Functions and Equations - Chapter Review - 9-1 and 9-2 Graphing Quadratic Functions - Page 590: 7

Please see the graph.

$y=x^2-4$ vertex: $x=-b/2a$ $x=-0/2*1$ $x=0$ $y=x^2-4$ $y=0^2-4$ $y=0-4 = -4$ $(0,-4)$ One other point on the line: $x=2$ $y=x^2-4$ $y=2^2-4$ $y=4-4 = 0$ $(2,0)$ The axis of symmetry is the blue line, and the vertex is labeled.