Answer
Please see the graph.
Work Step by Step
$y=2/3*x^2$
vertex:
$x=-b/2a$
$x=-0/2*2/3$
$x=0$
$y=2/3*x^2$
$y=2/3*(0)^2$
$y=2/3*0=0$
$(0,0)$
One other point on the graph:
$x=3$
$y=2/3*x^2$
$y=2/3*3^2$
$y=2/3*9=6$
$(3,6)$
The axis of symmetry is the blue line, and the vertex is labeled.