Chapter 9 - Quadratic Functions and Equations - Chapter Review - 9-1 and 9-2 Graphing Quadratic Functions - Page 590: 6

Please see the graph.

$y=-x^2+1$ vertex: $x=-b/2a$ $x=-0/2*-1$ $x=0$ $y=-x^2+1$ $y=-0^2+1$ $y=0+1$ $y=1$ $(0,1)$ One other point on the line: $x=1$ $y=-(1)^2+1$ $y=-1+1=0$ $(1,0)$ The vertex is labeled, and the axis of symmetry is the blue line.