Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 552: 46

Answer

t $\approx$ ± 2.83

Work Step by Step

$\frac{1}{2}$$t^{2}$ - 4 = 0 The first step is to add 4 to both sides: $\frac{1}{2}$$t^{2}$ - 4 + 4 = 0 + 4 $\frac{1}{2}$$t^{2}$ = 4 Next, divide both sides by $\frac{1}{2}$ (which is the same as multiplying by 2) to help isolate the t: 2($\frac{1}{2}$$t^{2}$) = 2(4) $t^{2}$ = 8 Lastly, take the square root of both sides: $\sqrt t^{2}$ = $\sqrt 8$ t = ± 2$\sqrt 2$ $\approx$ ± 2.83
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