Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 552: 44

Answer

± $\frac{3}{7}$

Work Step by Step

49$p^{2}$ - 16 = -7 Add 16 to both sides: 49$p^{2}$ - 16 + 16 = -7 + 16 49$p^{2}$ = 9 Divide both sides by 49: $\frac{49p^{2}}{49}$ = $\frac{9}{49}$ $p^{2}$ = $\frac{9}{49}$ Take the square root of both sides to get p by itself: $\sqrt p^{2}$ = $\sqrt \frac{9}{49}$ p = ± $\frac{3}{7}$
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