Answer
Please see the graph.
Work Step by Step
The graph was made using graphing software.
$f(x)= -2.5*x^2-x+3$
vertex:
$x=-b/2a$
$x = -(-1)/2*(-2.5)$
$x = 1/-5 = -1/5$
$f(-.2)= -2.5*(-.2)^2-(-.2)+3$
$f(-.2) = -2.5*.04 +.2+3$
$f(-.2) = -.1+.2+3$
$f(-.2) = 3.1$
$(-.2, 3.1)$
Two other points on the curve:
$x=0$
$f(0)= -2.5*(0)^2-(0)+3$
$f(0) = 0-0+3$
$f(0) = 3$
$(0,3)$
Since $(0,3)$ is .2 from the axis of symmetry, we also know $(.2, 3.1)$ is also on the curve.
