Answer
Please see the graph.
Work Step by Step
The graph was made using graphing software.
$y=1.5x^2-3x+2$
vertex
$x=-b/2a$
$x=-(-3)/2(1.5)$
$x = 3/3 = 1$
$y=1.5x^2-3x+2$
$y=1.5*1^2-3*1+2$
$y=1.5-3+2$
$y=.5$
$(1,.5)$
Two other points on the curve:
$x=0$
$y=1.5*0^2-3*0+2$
$y= 1.5*0 -0 +2$
$y = 0-0+2 = 2$
$(0,2)$
The distance from 0 to 1 (the axis of symmetry) is 1, so we also know $(2,2)$ is on the curve.
