Answer
Please see the graph.
Work Step by Step
The graph was created using graphing software.
$y=.25x^2-2x-1$
vertex
$x = -b/2a$
$x= -(-2)/2*(.25)$
$x = 2/.5 = 4$
$y=.25*4^2-2*4-1$
$y=.25*16 -8 -1$
$y=4 - 8-1$
$y = -5$
$(4, -5)$
Two other points on the line
$x=0$
$y=.25*0^2-2*0-1$
$y= .25*0 - 0 -1 $
$y = 0-0-1 = -1$
$(0,-1)$
The difference between 0 and 4 (the axis of symmetry) is 4, so the point $(8, -1)$ is also on the curve.
