Answer
($p^{3}$ + 18) ($p^{3}$ - 4)
Work Step by Step
Given the polynomial
$(p^{3})^{2}$ + 14$p^{3}$ - 72
*** We break of the middle term into two factors that add to give +14 and multiply to give -72. The two numbers are +18 and -4.
$(p^{3})^{2}$ + 18$p^{3}$ - 4$p^{3}$ - 72
We take the GCD of the first two and the GCD of the last two terms.
$p^{3}$($p^{3}$ + 18) -4 ($p^{3}$ + 18)
We take ($p^{3}$ + 18) and factor it out which gives us.
($p^{3}$ + 18) ($p^{3}$ - 4)
