Answer
($t^{4}$ + 8)($t^{4}$ - 3)
Work Step by Step
We write the polynomial
$(t^{4})^{2}$ + 5$t^{4}$ - 24
*** We break of the middle term into two factors that add to give +5 and multiply to give -24. The two numbers are +8 and -3.
$(t^{4})^{2}$ + 8$t^{4}$ - 3$t^{4}$ - 24
We take the GCD of the first two and the GDC of the last two terms.
$t^{4}$($t^{4}$ + 8) -3 ($t^{4}$ + 8)
We take ($t^{4}$ + 8) and factor it out which gives us.
($t^{4}$ + 8)($t^{4}$ - 3)
