Answer
($m^{5}$ + 17)($m^{5}$ + 1)
Work Step by Step
We write the polynomial
$(m^{5})^{2}$ + 18$m^{5}$ + 17
*** We break of the middle term into two factors that add to give +18 and multiply to give +17. The two numbers are +17 and +1.
$(m^{5})^{2}$ + 17$m^{5}$ + 1$m^{5}$ + 17
We take the GCD of the first two and the GCD of the last two terms.
$m^{5}$($m^{5}$ + 17) + 1 ($m^{5}$ + 17)
We take ($m^{5}$ + 17) and factor it out which gives us.
($m^{5}$ + 17)($m^{5}$ + 1)
