Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 5 - Linear Functions - 5-6 Parallel and Perpendicular Lines - Practice and Problem-Solving Exercises - Page 331: 27

Answer

Parallel: Lines a and f Perpendicular: Lines b and d, lines c and e

Work Step by Step

line a: $y = 3x + 3$ line b: $x = -1$ line c: $y - 5 = 1/2* (x-2)$ line d: $y = 3$ line e: $y + 4 = -2*(x+6)$ line f: $9x-3y =5$ Converting all lines (where possible) to slope-intercept form lines a, b, and d are already in slope-intercept form (or are horizontal or vertical lines) C: $y - 5 = 1/2* (x-2)$ $y - 5 = 1/2*x -1$ $y - 5+5 = 1/2*x -1+5$ $y = 1/2*x +4$ E: $y + 4 = -2*(x+6)$ $y + 4 = -2x - 12$ $y + 4 - 4 = -2x - 12 -4$ $y = -2x - 16$ F: $9x - 3y = 5$ $9x - 3y +3y -5= 5+3y -5$ $9x - 5 = 3y$ $3y = 9x-5$ $3y/3 = (9x-5)/3$ $y = 3x - 5/3$ line a: $y = 3x + 3$ line b: $x = -1$ line c: $y = 1/2*x +4$ line d: $y = 3$ line e: $y = -2x - 16$ line f: $y = 3x - 5/3$ Parallel lines have the same slope. Thus lines a and f are parallel ( $m= 3$). Perpendicular lines have a product of their slopes equal to -1. Thus, lines c and e are perpendicular. Also, lines b and d are perpendicular since the angle made by the two lines is a 90 degree angle (definition of perpendicular).
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.