Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 623: 8

$t=49$

$Given,$ $\sqrt t + 2=9$ $\sqrt t + 2-2=9-2$ $\sqrt t=7$ Squaring,we get: $t=49$ We need to check by putting the obtained value in the original equation : $L.H.S=\sqrt 49 + 2=7 + 2=9=R.H.S$ Hence, $t=49$ is a valid solution