Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 623: 20

$y=3$

$Given,$ $\sqrt (2y)$$=\sqrt (9-y)$ Squaring,we get: $2y=9-y$ $3y=9$ $y=9\div3=3$ We need to check by putting the obtained value in the original equation : $L.H.S=\sqrt(2X3) =\sqrt 6=\sqrt (9-3)=R.H.S$ Hence,$y=3$ is a valid solution