Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 623: 12

$t=25$

$Given,$ $3-\sqrt t=-2 $ $3+2-\sqrt t=-2+2$ $5-\sqrt t=0$ $\sqrt t=5$ Squaring,we get: $t=25$ We need to check by putting the obtained value in the original equation : $L.H.S=3-\sqrt 25=3-5=-2=R.H.S$ Hence,$t=25$ is a valid solution