Answer
x=-5,5
Work Step by Step
In order to solve the equation x2-25=0 we will factor the left side of the equation by applying the rule that states
$a^2-b62=(a+b)(a-b)$
If we set $a^2=x^2$
and $b^2=25$, we can solve for a and b.
$a^2=x^2$
After we square root both sides of the equation, we will get
a=x
$b^2=25$
After we square root both sides of equation, we will go
b=5
Therefore,
$x^2-25=(x+5)(x-5)$
And if $x^2-25=0$, then we can set x+5=0 and x-5=0
For x+5=0, we can solve for x by subtracting 5 from both sides of the equation, and getting
x=-5
For x-5=0, we can solve for x by adding 5 to both sides of the equation, and getting
x=5
