Answer
$x=1$ or $x=-\frac{7}{3}$
Work Step by Step
We are given
$12x^2+16x-28=0$
$3x^2+4x-7=0$
$(x-1)(3x+7)=0$
$x-1=0$ or $3x+7=0$
$x=1$ or $x=-\frac{7}{3}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - Chapter Test - Page 607: 17
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