Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - Chapter Test - Page 607: 19

Answer

$2.05$ seconds.

Work Step by Step

The given function is $\Rightarrow h=-16t^2+30t+6$ At the ground $h=0\;feet$. Substitute the value of $h$ into the function. $\Rightarrow 0=-16t^2+30t+6$ Divide the equation by $2$. $\Rightarrow 0=-8t^2+15t+3$ Use the quadratic formula to solve for $t$. $t=\frac{-15\pm\sqrt{15^2-4(-8)(3)}}{2(-8)}$ Simplify. $t=\frac{-15\pm\sqrt{225+96}}{-16}$ $t=\frac{-15\pm\sqrt{321}}{-16}$ $t=2.05$ (Rounded to two decimal places). Hence, the time is $2.05$ seconds.
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