Answer
See answers below
Work Step by Step
$f(x)=6x^2+6x-5$
Find the axis of symmetry and the coordinates of the vertex.
$x=\frac{-b}{2a}=\frac{-6}{2.6}=\frac{-1}{2}$
The axis of symmetry is $x = \frac{-1}{2}$. So the x-coordinate of the vertex is $\frac{-1}{2}$.
Substitute 1 for x to find the y-coordinate of the vertex.
$y=6(\frac{-1}{2})^2+6(\frac{-1}{2})-5$
$y=\frac{-13}{2}$
The vertex is $(\frac{-1}{2},\frac{-13}{2})$
Find two other points on the graph.
$(0,-5)$
$(2,-5)$
Graph the vertex and the points we found.
